
To calculate the compensation capacitor value, you can use the following formulas:For Farads:[ C = \frac{kVAR}{2\pi f V^2} ]For Microfarads:[ C = \frac{kVAR \times 10^9}{2\pi f V^2} ]Where:( C ) is the capacitance in Farads or Microfarads,( kVAR ) is the reactive power in kilovolt-amperes reactive,( f ) is the frequency in hertz,( V ) is the voltage in volts1.Additionally, when selecting the value of a compensation capacitor in amplifier circuits, consider the specific application and test the circuit to verify if the selected capacitor is appropriate2. [pdf]
The k factor is read from a table 1 – Multipliers to determine capacitor kilovars required for power factor correction (see below) and multiplied by the effective power. The result is the required capacitive power. For an increase in the power factor from cosφ = 0.75 to cosφ = 0.95, from the table 1 we find a factor k = 0.55:
For each step power rating (physical or electrical) to be provided in the capacitor bank, calculate the resonance harmonic orders: where S is the short-circuit power at the capacitor bank connection point, and Q is the power rating for the step concerned.
Take measurements over a significant period (minimum one week) of the voltages, currents, power factor, level of harmonics (individual and global THD-U/THD-I). Size the capacitor bank appropriately for its reactive energy compensation requirements, based on these measurements and your electricity bills.
For better efficiency, capacitor bank should be chosen wisely. Under size capacitor bank will not benefit, as electricity bill will still be high due to high power factor. Power : In kW. Connection Type : Single phase or 3-phase.
Technically, this will be total VA, but in absence of working power this result will be close to VAR. Once you determined "Q L ", the required rating of PFC capacitors will be simply Qc=QL×PFdesired, where PF is given as a decimal. If you are unable to determine no-load VAR, things get a bit more complicated.
To calculate the required PFC capacitance we need to know the existing reactive power Q L (VAR) of your electrical system and choose desired PF. The problem is Q L is not always known. There are several ways of estimating Q L, depending on what other quantities are known. We will discuss these methods below.

The RC time constant, denoted τ (lowercase ), the (in ) of a (RC circuit), is equal to the product of the circuit (in ) and the circuit (in ): It is the required to charge the , through the , from an initial charge voltage of zero to approximately 63.2% of the value of an applied A smaller time constant means the capacitor charges or discharges more quickly, resulting in a faster rate of change. The time constant is also used to determine the frequency response of the circuit. [pdf]
Thus the time constant of the circuit is given as the time taken for the capacitor to discharge down to within 63% of its fully charged value.
Thus every time interval of tau, (τ) the voltage across the capacitor increases by e-1 of its previous value and the smaller the time constant tau, the faster is the rate of change. We can show the variation of the voltage across the capacitor with respect to time graphically as follows:
An RC series circuit has a time constant, tau of 5ms. If the capacitor is fully charged to 100V, calculate: 1) the voltage across the capacitor at time: 2ms, 8ms and 20ms from when discharging started, 2) the elapsed time at which the capacitor voltage decays to 56V, 32V and 10V.
So after 3 seconds, the capacitor is charged to 63% of the 9 volts that the battery is supplying it, which would be approximately 5.67 volts. If R=1KΩ and C=1000µF, the time constant of the circuit is τ=RC= (1KΩ) (1000µF)=1 second. If R=330KΩ and C=0.05µF, the time constant of the circuit is τ=RC= (330KΩ) (0.05µF)=16.5ms.
That is, at 5T the capacitor is “fully charged”. An RC series circuit has resistance of 50Ω and capacitance of 160µF. What is its time constant, tau of the circuit and how long does the capacitor take to become fully charged. 1. Time Constant, τ = RC. Therefore: τ = RC = 50 x 160 x 10-6 = 8 ms 2. Time duration to fully charged:
The result is that unlike the resistor, the capacitor cannot react instantly to quick or step changes in applied voltage so there will always be a short period of time immediately after the voltage is firstly applied for the circuit current and voltage across the capacitor to change state.
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